Question

Calculate the number of disintegrations per second that occur in 100 g of radium given that the decay constant is 1.36 x 10−11 radium?

Answer 1

Answer on Question #55005 – Chemistry – Other

Question:

Calculate the number of disintegrations per second that occur in $100\,\mathrm{g}$ of radium given that the decay constant is $1.36 \times 10^{-11}$ radium?

$$dN = -N_0 \times t \times \lambda$$

$dN$ – number of disintegrations per period of time

$N_0$ – total number of particles in the sample

$t$ – period of time

$\lambda$ – the decay constant

$$N_0 = \frac{100 \times 6.022 \times 10^{23}}{226}$$ $$dN = 2.66 \times 10^{23} \times 1 \times 1.36 \times 10^{-11}$$ $$dN = 3.617 \times 10^{12}$$

Answer: $3.617 \times 10^{12}$ Bq

www.AssignmentExpert.com