Question

If Fe2+ spontaneously oxidized by the oxygen of the air in acidic solution? Calculate ΔG and K.

Answer 1

Answer on Question #55004 – Chemistry – Other

Task:

If $\mathrm{Fe}^{2+}$ spontaneously oxidized by the oxygen of the air in acidic solution? Calculate $\Delta G$ and $K$ .

Solution:

$$\mathrm{Fe}^{2+} + \frac{1}{4} \mathrm{O}_2 + \mathrm{H}^+ \rightarrow \mathrm{Fe}^{3+} + \frac{1}{2} \mathrm{H}_2\mathrm{O}$$ $$\Delta G^{\circ} = -84.88 \ \mathrm{kJ/mol}$$ $$\Delta G^{\circ} = -\mathrm{RT \ ln \ K}$$ $$\ln K = \Delta G^{\circ} / -\mathrm{RT}$$ $$R = 0.008144621 \ \mathrm{kJ \ K^{-1} \cdot mol^{-1}}$$ $$\ln K = -84.88 / (-0.008144621 \cdot 298) = 34.93$$ $$K = 1.5 \cdot 10^{15}$$

Answer:

$$\Delta G^{\circ} = -84.88 \ \mathrm{kJ/mol}, \ K = 1.5 \cdot 10^{15}$$

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