Question

Calculate the number of mole contained in a solution of sulphuric acid, if the titre value on titration against
20cm3
0.5 M sodium carbonate is
20.24cm3
0.02mol
0.04mol
0.01mol
0.15mol

Answer 1

Answer on Question #54283 – Chemistry – General Chemistry

Task:

Calculate the number of mole contained in a solution of sulphuric acid, if the titre value on titration against 20 cm³ 0.5 M sodium carbonate is 20.24 cm³:

- 0.02 mol

- 0.04 mol

- 0.01 mol

- 0.15 mol

Answer:

$$\mathrm{H_2SO_4} + \mathrm{Na_2CO_3} = \mathrm{Na_2SO_4} + \mathrm{H_2O} + \mathrm{CO_2}$$

Titre =

$$C_M = \frac{v}{V} \quad v = C_M \cdot V$$ $$v(H_2SO_4) = v(Na_2CO_3)$$ $$v(H_2SO_4) = C_M(H_2SO_4) \cdot V(H_2SO_4) = 0.5 \cdot 0.02$$ $$v(H_2SO_4) = 0.01 \text{ moles}$$

So, the number of moles contained in a solution of sulphuric acid is 0.01 moles.

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