Question

If 5cm3 of 1.5 M of NaCl is diluted to a final volume of 5dm3. what is its final concentration?

Answer 1

Answer on Question #54221 – Chemistry – Other

Question:

If $5\mathrm{cm}^3$ of 1.5 M of NaCl is diluted to a final volume of $5\mathrm{dm}^3$. What is its final concentration?

Answer:

Formula is $c_1V_1 = c_2V_2$, where $c_1$ – first concentration (1.5 M), $c_2$ – second concentration, $v_1$ – first volume ($5\mathrm{cm}^3$), $v_2$ – second volume ($5\mathrm{dm}^3$).

$$c_2 = c_1v_1/v_2 = 1.5M \times 0.005\mathrm{dm}^3/5\mathrm{dm}^3 = 0.0015M$$

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