Question

a solution of 7.8gms of C6H6 and 45gms of C6H5CH3. calculate mole fraction of C6H6 and C6H5CH3

Answer 1

Answer to Question #52606, Chemistry, Other

a solution of 7.8 gms of $\mathrm{C_6H_6}$ and 45 gms of $\mathrm{C_6H_5CH_3}$ . calculate mole fraction of $\mathrm{C_6H_6}$ and $\mathrm{C_6H_5CH_3}$

Answer:

$$n = \frac {m}{M _ {r}}$$ $$n \left(C _ {6} H _ {6}\right) = \frac {7 . 8}{7 8} = 0. 1 \text{ mol}$$ $$n \left(C _ {6} H _ {5} C H _ {3}\right) = \frac {4 5}{9 2} = 0. 4 8 9 \text{ mol}$$ $$n _ {\Sigma i} = 0. 1 + 0. 4 8 9 = 0. 5 8 9 \text{ mol}$$ $$\phi \left(C _ {6} H _ {6}\right) = \frac {0 . 1}{0 . 5 8 9} = 0. 1 7$$ $$\phi \left(C _ {6} H _ {5} C H _ {3}\right) = \frac {0 . 4 8 9}{0 . 5 8 9} = 0. 8 3$$

0.83 of $\mathrm{C_6H_5CH_3}$ and 0.17 of $\mathrm{C_6H_6}$

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