Question

Phosphorus-32 is used in the treatment of leukemia. It has a half-life of 14 days. If a
sample received by a medical lab has a mass of 16.0 g, how many grams of the
sample is still active 8.0 weeks later. Assume 1 week = 7 days.

Answer 1

Answer on Question #52397, Chemistry, Other

**Task:**

Phosphorus-32 is used in the treatment of leukemia. It has a half-life of 14 days. If a sample received by a medical lab has a mass of 16.0 g, how many grams of the sample is still active 8.0 weeks later. Assume 1 week = 7 days.

**Answer:**

$$N = \frac{N_o}{\frac{t}{2^t}}$$

where:

N – resulting amount of the active substance, g;

N₀ – initial amount of the active substance, g;

T – elapsed time, days;

t – half-life time, days.

$$N(P - 32) = \frac{16}{2^{14}} = 1\ \text{g}$$

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