Question #51901

3.47g sodium carbonate was dissolved in a 250millilitre standard flask. What is the concentration of the resulting solution
0.13M
0.52M
0.66M
0.40M

Expert's answer

Answer on Question #51901 - Chemistry - Other

Question

3.47g sodium carbonate was dissolved in a 250millilitre standard flask. What is the concentration of the resulting solution

0.13M

0.52M

0.66M

0.40M

Answer:

Molar concentration of the solution is:


C=nV=mMVC = \frac{n}{V} = \frac{m \cdot M}{V}


M – Molar mass of sodium carbonate, M(Na2CO3)=106 g/mol\mathrm{M}(\mathrm{Na}_2\mathrm{CO}_3) = 106\ \mathrm{g/mol}

C=mMV=3.471060.250=0.13 mol/LC = \frac{m \cdot M}{V} = \frac{3.47 \cdot 106}{0.250} = 0.13\ \mathrm{mol/L}


Answer: 0.13 M

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