Question

If
15cm3
of 10.25M HCl solution is made up to volume in a 500 Ml volumetric flask, what will be its new concentration?
0.306M
3.06M
5.13M
0.52M

Answer 1

Answer on Question #51870 - Chemistry – Other

Question

If 15cm³ of 10.25M HCl solution is made up to volume in a 500 Ml volumetric flask, what will be its new concentration?

0.306M

3.06M

5.13M

0.52M

Answer:

Number of moles of HCl in the initial solution is:

$$n(HCl) = C_1 V_1 = 10.25 \cdot 0.015 = 0.153 \text{ mol}$$

New molar concentration of the solution is:

$$C_2 = \frac{n}{V_2} = \frac{0.153}{0.5} = 0.306 \text{ M}$$

Answer: 0.306 M

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