Question

C3H8 + 5O2 → 3CO2 + 4H2O What is the theoretical yield of in grams of water if the reaction started with 14.8 g C3H8 and 3.44 g O2?

Answer 1

Answer to Question #50867, Chemistry, Other

$\mathrm{C}_{3} \mathrm{H}_{8} + 5 \mathrm{O}_{2} \rightarrow 3 \mathrm{CO}_{2} + 4 \mathrm{H}_{2} \mathrm{O}$ What is the theoretical yield of in grams of water if the reaction started with $14.8 \mathrm{~g} \mathrm{C}_{3} \mathrm{H}_{8}$ and $3.44 \mathrm{~g} \mathrm{O}_{2}$ ?

Solution:

$$n \left(H _ {2} O\right) = \frac {4}{5} n \left(O _ {2}\right) = \frac {4}{5} \times 0. 1 0 7 5 = 0. 0 8 6 m o l$$ $$m \left(H _ {2} O\right) = 1 8 \frac {g}{m o l} \times 0. 0 8 6 m o l = 1. 5 4 8 g$$

Answer:

1.548 g of $\mathsf{H}_2\mathsf{O}$

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