Question #50480

What volume of 5.0 M HNO3 is required to neutralize 2500 cm3 of a 2.0 M NaOH solution

Expert's answer

Answer on Question #50480, Chemistry, Other

What volume of 5.0 M HNO₃ is required to neutralize 2500 cm³ of a 2.0 M NaOH solution?

Solution:


HNO3+NaOHNaNO3+H2O\mathrm{HNO_3} + \mathrm{NaOH} \rightarrow \mathrm{NaNO_3} + \mathrm{H_2O}n=C×Vn = C \times Vn(HNO3)=n(NaOH)n(HNO_3) = n(NaOH)C1×V1=C2×V2C_1 \times V_1 = C_2 \times V_2V2=C1×V1C2=2500 cm3×2.0 M5.0 M=1000 cm3V_2 = \frac{C_1 \times V_1}{C_2} = \frac{2500\ \mathrm{cm^3} \times 2.0\ \mathrm{M}}{5.0\ \mathrm{M}} = 1000\ \mathrm{cm^3}


Answer:

1000 cm³ of HNO₃

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