Question

3. If an excess of nitrogen gas reacts with 250 L of hydrogen gas, according to the reaction below, how many L of ammonia will be produced?

N2(g) + 3H2(g) ---> 2NH3(g)



4. How many cm3 of oxygen would be required to react completely with 432 cm3 of hydrogen gas according to the reaction below?

2H2(g) + O2(g) ---> 2H2O(g)

Answer 1

3. For solving this problem we can use the proportion: 3moles/2moles =250L/x L and we get: x = 250*2/3 = 166.7L
4. With using the proportion we get 2moles/1mole= 432cm3/x cm3, so x = 432/2 = 216cm3