Question #50409

1. How many atoms does 2.0 moles of He represent?
2. How many sodium ions are in 3.0 moles of NaCl?
3. How many molecules are in 0.25 moles of CH4?
4. How many total atoms are in 1.0 moles of H20?

Expert's answer

Question:

1. How many atoms does 2.0 moles of He represent?

2. How many sodium ions are in 3.0 moles of NaCl?

3. How many molecules are in 0.25 moles of CH4\mathrm{CH}_4?

4. How many total atoms are in 1.0 moles of H2O\mathrm{H}_2\mathrm{O}?

Answer:

1. How many atoms does 2.0 moles of He represent?

We use the following formula to calculate the number of atoms:


n (mol)=N(number of atoms)/NAn \text{ (mol)} = N_{\text{(number of atoms)}} / N_AN(He)=n(mol)NAN_{\text{(He)}} = n_{\text{(mol)}} \cdot N_AN(He)=2.0 moles6.021023=12.041023 atomsN_{\text{(He)}} = 2.0 \text{ moles} \cdot 6.02 \cdot 10^{23} = 12.04 \cdot 10^{23} \text{ atoms}


2. How many sodium ions are in 3.0 moles of NaCl?


n (mol)=N(number of ions)/NAn \text{ (mol)} = N_{\text{(number of ions)}} / N_A


1 molecule of NaCl contains 1 sodium ion (Na+\mathrm{Na}^{+}), that's why if we have 3.0 moles of NaCl, we have 3.0 moles of Na+\mathrm{Na}^{+}.


N(ions)=n(mol)NAN_{\text{(ions)}} = n_{\text{(mol)}} \cdot N_AN(ions)=3.0 moles6.021023=18.061023 ionsN_{\text{(ions)}} = 3.0 \text{ moles} \cdot 6.02 \cdot 10^{23} = 18.06 \cdot 10^{23} \text{ ions}


3. How many molecules are in 0.25 moles of CH4\mathrm{CH}_4?


n (mol)=N(number of molecules)/NAn \text{ (mol)} = N_{\text{(number of molecules)}} / N_AN(molecules)=n(mol)NAN_{\text{(molecules)}} = n_{\text{(mol)}} \cdot N_AN(molecules)=0.25 moles6.021023=1.5051023 moleculesN_{\text{(molecules)}} = 0.25 \text{ moles} \cdot 6.02 \cdot 10^{23} = 1.505 \cdot 10^{23} \text{ molecules}


4. How many total atoms are in 1.0 moles of H2O\mathrm{H}_2\mathrm{O}?

1 molecule of H2O\mathrm{H}_2\mathrm{O} contains 3 atoms (two hydrogen & one oxygen), that's why if we have 1.0 moles of H2O\mathrm{H}_2\mathrm{O}, we have 3.0 moles of atoms.


N(atoms)=n(mol)NAN_{\text{(atoms)}} = n_{\text{(mol)}} \cdot N_AN(atoms)=3.0 moles6.021023=18.061023 atomsN_{\text{(atoms)}} = 3.0 \text{ moles} \cdot 6.02 \cdot 10^{23} = 18.06 \cdot 10^{23} \text{ atoms}


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