Question

What is the pOH of a solution with a [OH -] concentration of 9.7 X 10 -11 M?

Answer 1

Answer on Question #50375, Chemistry, Other

What is the pOH of a solution with a $[\mathrm{OH}^{-}]$ concentration of $9.7 \times 10^{-11} \mathrm{M}$?

Solution:

$$pOH = - \log_{10} [OH^{-}]$$ $$pOH = - \log_{10} 9.7 \times 10^{-11} = 10.01$$

Answer:

$$\mathrm{pOH} = 10.01$$

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