Question

If an excess of nitrogen gas reacts with 250 L of hydrogen gas, according to the reaction below, how many L of ammonia will be produced?

N2(g) + 3H2(g) ---> 2NH3(g)

Answer 1

Answer on Question#50360 – Chemistry – Other

If an excess of nitrogen gas reacts with 250 L of hydrogen gas, according to the reaction below, how many L of ammonia will be produced?

$$\mathrm{N_2(g)} + 3\mathrm{H_2(g)} \longrightarrow 2\mathrm{NH_3(g)}$$

Solution:

According to the Gay-Lussacc's law:

$$V(H_2) : V(NH_3) = 3 : 2;$$ $$\frac{250}{x} = \frac{3}{2}; \quad x = 166.7\ \text{L}$$ $$V(NH_3) = 166.7\ \text{L}$$

Answer: 166.7 L

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