Question

When 75.0 dm3 of O2 react with an excess of glucose (C6H12O2), according to the reaction below, what volume of carbon dioxide will be produced?

6O2(g) + C6H12O6(s) ---> 6H2O(g) + 6CO2(g

Answer 1

From the equation
6O₂ + C₆H₁₂O₆ -> 6H₂O +6CO₂
one can see that there isproduced as much moles of CO₂ as moles of O₂ reacted, andsince both are gases their volumes are equal as well.
Since 6H₂O is inexcess all given O₂ will react, i.e. 75 dm­­³.
Therefore, 75 dm³ of CO₂will be produced.