Answer on Question #50324, Chemistry, Other
Task:
How many grams of magnesium oxide (MgO) are produced when 1200 grams of magnesium (Mg) burn in an excess of oxygen, as shown below?
2Mg + O₂ ---> 2MgO
Answer:
ν=MmM(Mg)=24.3g/molM(MgO)=40.3g/molν(Mg)=24.31200=49.4molν(Mg)=ν(MgO)=49.4molm(MgO)=ν(MgO)⋅M(MgO)m(MgO)=49.4⋅40.3=1990.1g
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