Question

How much mass does 1.51 x 1022 atoms of neon represent?

Answer 1

Answer on Question #50320 - Chemistry – Other

Question

How much mass does $1.51 \times 10^{22}$ atoms of neon represent?

Answer:

Calculate the mass of $1.51 \times 10^{22}$ atoms of neon. The formula is:

$$m = \frac{N \cdot M}{N_A}$$

N – Number of atoms, N = $1.51 \times 10^{22}$ g;

$N_A$ – Avogadro constant, $N_A = 6.022 \cdot 10^{23} \ \mathrm{mol}^{-1}$;

M – molar mass of neon, M = 20.2 g/mol.

The mass of $1.51 \times 10^{22}$ atoms of neon is:

$$m = \frac{1.51 \cdot 10^{22} \cdot 20.2}{6.022 \cdot 10^{23}} = 0.5 \ g$$

Answer: 0.5 g

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