Question #50319

What would be the mass of 2.41 x 1024 formula units of barium hydroxide?

Expert's answer

Answer on Question #50319, Chemistry, Other

What would be the mass of 2.41×10242.41 \times 10^{24} formula units of barium hydroxide?

Solution:

Barium hydroxide is Ba(OH)2\mathrm{Ba(OH)_2}

Mr=171.34 g/molM_r = 171.34\ \mathrm{g/mol}

NA=6.02×1023 mol1N_A = 6.02 \times 10^{23}\ \mathrm{mol}^{-1}

n=NNA=mMrn = \frac{N}{N_A} = \frac{m}{M_r}m=Mr×NNAm = \frac{M_r \times N}{N_A}m=171.34 g/mol×2.41×10246.02×1023 mol=685.93 gm = \frac{171.34\ \mathrm{g/mol} \times 2.41 \times 10^{24}}{6.02 \times 10^{23}\ \mathrm{mol}} = 685.93\ \mathrm{g}


Answer:

685.93 g of barium hydroxide

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