Question

What would be the mass of 1.20 x 1024 molecules of water?

Answer 1

Answer on the question #50318, Chemistry, Other

Question:

What would be the mass of $1.20 \times 10^{24}$ molecules of water?

Solution:

The mass of number of molecules is easy to calculate, if we convert it to the number of the mole:

$$\left( \begin{array}{c} N = n * N _ {A} \\ m = n * M \end{array} \right) \Rightarrow m = \frac {N}{N _ {A}} * M,$$

Where $n$—number of the moles,

$N_{A}$—Avogadro number, $6.02 * 10^{23} \mathrm{~mol}^{-1}$,

$M$—molar mass of water, 18 g/mol.

$$m = \frac {1.2 * 10^{24}}{6.02 * 10^{23}} * 18 = 35.9 \mathrm{g}$$

Answer: 35.9 g.

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