Question #50204

*determining molar mass* Pb(NO3)2

Expert's answer

Answer on Question #50204 - Chemistry - Other

Question

*determining molar mass* Pb(NO₃)₂

Answer:

Molar mass of Pb(NO₃)₂ equals:


M(Pb(NO3)2)=M(Pb)+2(M(N)+3M(O))=207.2+2(14.0+316.0)=331.2 g/moleM(Pb(NO₃)₂) = M(Pb) + 2(M(N) + 3M(O)) = 207.2 + 2(14.0 + 3 \cdot 16.0) = 331.2 \text{ g/mole}

Answer: 331.2 g/mole

https://www.AssignmentExpert.com

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS