Question

How many molecules does 11.0 grams of CO2 represent?

Answer 1

Answer on Question #50180, Chemistry, Other

How many molecules does 11.0 g of CO₂ represent?

Solution:

$$n = \frac{m}{M_r} = \frac{V}{V_m} = \frac{N}{N_a}$$ $$\frac{m}{M_r} = \frac{N}{N_a}$$ $$N = \frac{m \times N_a}{M_r}$$

Where m – mass of compound,

M_r – molecular mass of compound and

N_a – Avogadro constant, 6.022 × 10²³ mol⁻¹

In case of CO₂ Mr = 12 + 2 × 16 = 44 g/mol

Thus

$$N = \frac{11\,g \times 6.022 \times 10^{23}\,mol^{-1}}{44\,g/mol} = 1.5055 \times 10^{23}$$

Answer:

1.5055 × 10²³ molecules

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