Question

a 55 g sample of water at 80 degrees celcius is added to a sample of water at 25.5 degrees celcius in a constant pressure calorimeter. If the final temperature of the combined water is 39.4 degrees celcius calculate the mass of water originally in the calorimeter.

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Answer 1

Answer on Question #49859, Chemistry, Other

**Task:**

A 55 g sample of water at 80 degrees celcius is added to a sample of water at 25.5 degrees celcius in a constant pressure calorimeter. If the final temperature of the combined water is 39.4 degrees celcius calculate the mass of water originally in the calorimeter.

**Answer:**

$$Q = c m \Delta T$$ $$c _ {1} m _ {1} \Delta T _ {1} = c _ {2} m _ {2} \Delta T _ {2}$$ $$c (H _ {2} O) = 4, 1 8 2 \frac {k J}{k g \cdot^ {o} C}$$ $$4, 1 8 2 \cdot 5 5 \cdot (8 0 - 3 9, 4) = 4, 1 8 2 \cdot m _ {2} (3 9, 4 - 2 5, 5)$$ $$m _ {2} = \frac {5 5 \cdot (8 0 - 3 9 , 4)}{(3 9 , 4 - 2 5 , 5)} = 1 6 0, 6 g$$

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