Question

Calculate the e.m.f. of a copper-zinc voltaic cell working with the following electrolytes 0.001 M CuSO4 and 0.001 M ZnSO4.?

Answer 1

Question #49807, Chemistry, Other

Calculate the e.m.f. of a copper-zinc voltaic cell working with the following electrolytes 0.001 M CuSO4 and 0.001 M ZnSO4.?

Answer:

$$EMF = E_1 - E_2$$ $$EMF = E_{Cu2+/Cu} - E_{Zn2+/Zn}$$ $$E_{Cu2+/Cu} = E_{Cu2+/Cu}^* + \frac{RT}{nF} \ln a_{Cu2+} = 0.34 + \frac{RT}{nF} \ln 0.001$$ $$E_{Zn2+/Zn} = E_{Zn2+/Zn}^* + \frac{RT}{nF} \ln a_{Zn2+} = -0.76 + \frac{RT}{nF} \ln 0.001$$ $$EMF = 0.34 + \frac{RT}{nF} \ln 0.001 - (-0.76 + \frac{RT}{nF} \ln 0.001) = 1 \, \text{V}$$

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