Question #49606

1. Calculate the no. Of grams of water that must be added to 16 grams of sugar in the preparation of 25% sugar solution
2. Calculate the grams of solute that must be dissolve in a. 350g of water in the preparation of 15% potassium sulfate solution b. 15g of water in the preparation of 10% sodium chloride solution

Expert's answer

Answer on Question #49606, Chemistry, Other

**Task:**

1. Calculate the no. Of grams of water that must be added to 16 grams of sugar in the preparation of 25% sugar solution

2. Calculate the grams of solute that must be dissolve in

a. 350 g of water in the preparation of 15% potassium sulfate solution

b. 15 g of water in the preparation of 10% sodium chloride solution

**Answer:**

1)


%=m(sugar)m(sugar)+m(H2O)100%\% = \frac{m_{(sugar)}}{m_{(sugar)} + m(H_2O)} \cdot 100\%25%=1616+m(H2O)100%25\% = \frac{16}{16 + m(H_2O)} \cdot 100\%m(H2O)=161002516=48 gm(H_2O) = \frac{16 \cdot 100}{25} - 16 = 48\ g


2)a)


%=m(K2SO4)m(K2SO4)+m(H2O)100%\% = \frac{m_{(K_2SO_4)}}{m_{(K_2SO_4)} + m_{(H_2O)}} \cdot 100\%15%=m(K2SO4)m(K2SO4)+350100%15\% = \frac{m_{(K_2SO_4)}}{m_{(K_2SO_4)} + 350} \cdot 100\%m(K2SO4)=0.15(m(K2SO4)+350)m_{(K_2SO_4)} = 0.15(m_{(K_2SO_4)} + 350)m(K2SO4)=61.8 gm_{(K_2SO_4)} = 61.8\ g


b)


%=m(NaCl)m(NaCl)+m(H2O)100%\% = \frac{m_{(NaCl)}}{m_{(NaCl)} + m_{(H_2O)}} \cdot 100\%10%=m(NaCl)m(NaCl)+15100%10\% = \frac{m_{(NaCl)}}{m_{(NaCl)} + 15} \cdot 100\%m(NaCl)=0.1(m(NaCl)+15)m_{(NaCl)} = 0.1(m_{(NaCl)} + 15)m(NaCl)=1.67 gm_{(NaCl)} = 1.67\ g


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