Question #49600

Plutonium-240 (Pu-240) is a byproduct of the nuclear reaction that takes place in a reactor. It takes one thousand years for 10.0% of a 4.60-g sample to decay.
A. What is the half-life of PU-240?
B. How long will it take to reduce a 2.00-g sample to 15% of its original amount?
C. What is the rate of decay of a 5.00-g sample in g/year?

Expert's answer

Answer on Question #49600, Chemistry, Other

**Task:**

Plutonium-240 (Pu-240) is a byproduct of the nuclear reaction that takes place in a reactor. It takes one thousand years for 10.0% of a 4.60-g sample to decay.

A. What is the half-life of PU-240?

B. How long will it take to reduce a 2.00-g sample to 15% of its original amount?

C. What is the rate of decay of a 5.00-g sample in g/year?

**Answer:**

A. Half-life of an element is a period, during which a half amount of the element is decayed.


[Pu240]=4,60,14,6=4,14 g[Pu - 240] = 4,6 - 0,1 \cdot 4,6 = 4,14\ gln4,6ln4,14=k(1000 y)k=1.05104 y1\ln 4,6 - \ln 4,14 = k(1000\ y)\quad k = 1.05 \cdot 10^{-4}\ y^{-1}t1/2=0,6931.05104 y1=6,6103 yt_{1/2} = \frac{0,693}{1.05 \cdot 10^{-4}\ y^{-1}} = 6,6 \cdot 10^{-3}\ y


B.


[Pu240]=0,152.00=0,30 g[Pu - 240] = 0,15 \cdot 2.00 = 0,30\ gln2,00ln0,30=(1,05104 y1) tt=1.8104 y1\ln 2,00 - \ln 0,30 = (1,05 \cdot 10^{-4}\ y^{-1})\ t\quad t = 1.8 \cdot 10^{4}\ y^{1}


C. Rate = (1.05104 y1)5,00=5.25104 g/y(1.05 \cdot 10^{-4}\ y^{-1}) \cdot 5,00 = 5.25 \cdot 10^{-4}\ g / y

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