Question

In the following reaction, how many grams of calcium hydroxide, Ca(OH)2, will be needed to react with 75.1 g of hydrochloric acid, HCl?

Answer 1

Answer on Question #49493 - Chemistry - Other

Question

In the following reaction, how many grams of calcium hydroxide, $\mathrm{Ca(OH)}_2$, will be needed to react with $75.1\ \mathrm{g}$ of hydrochloric acid, HCl?

Answer:

Reaction between calcium hydroxide and hydrochloric acid:

$$\mathrm{Ca(OH)}_2 + 2\mathrm{HCl} = \mathrm{CaCl}_2 + 2\mathrm{H}_2\mathrm{O}$$

Number of moles of HCl is:

$$n = \frac{m}{M} = \frac{75.1}{36.5} = 2.06\ \mathrm{moles}$$

According to the reaction, 2 moles of HCl react with 1 mole of $\mathrm{Ca(OH)}_2$, therefore, 2.06 moles of HCl react with 1.03 moles of $\mathrm{Ca(OH)}_2$.

Then the mass of calcium hydroxide needed is:

$$\mathrm{m}(\mathrm{Ca(OH)}_2) = \mathrm{nM} = 1.03 \cdot 74 = 76.22\ \mathrm{g}$$

Answer: 76.22 g

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