Answer on Question #49465, Chemistry, Other
**Task:**
What mass of copper (II) nitrate is required to prepare a 0.500 L of a 0.750 mol/L solution?
**Answer:**
CM=Vvv=Mmv(CuNO3)=CM(CuNO3)⋅V(CuNO3)m(CuNO3)=v(CuNO3)⋅M(CuNO3)M(CuNO3)=125.5 g/molv(CuNO3)=0,750⋅0,5=0,375 molm(CuNO3)=0,375⋅125,5=47,06 g
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