Question

using word equations and turning them into chemical equations and balancing them. (also writing the state of matter)

1) a double displacement reaction occurs between aqueous calcium hydroxide and lithium fluoride.
2) Aqueous forms of lead ll nitrate and potassium sulfate react, with a product being a precipitate of lead ll sulfate.
3. Aqueous sodium carbonate and silve l nitrite are reactants in a double displacement reaction.
4. when crystalline C6H12O6 is burned into oxygen a combustion reaction occurs.

Answer 1

Answer on the question #49329, Chemistry, Other

Question:

using word equations and turning them into chemical equations and balancing them. (also writing the state of matter)

1) a double displacement reaction occurs between aqueous calcium hydroxide and lithium fluoride.

2) Aqueous forms of lead II nitrate and potassium sulfate react, with a product being a precipitate of lead II sulfate.

3. Aqueous sodium carbonate and silve I nitrite are reactants in a double displacement reaction.

4. when crystalline C6H12O6 is burned into oxygen a combustion reaction occurs.

Answer:

1) Calcium hydroxide(aq) + lithium fluoride(aq) = calcium fluoride + lithium hydroxide(aq)

$\mathrm{Ca(OH)_2}$ (aq) + 2LiF(s) = CaF₂ (aq) + 2LiOH(aq)

2) Lead nitrate (aq) + sodium sulfate (aq) = lead sulfate (s) + potassium nitrate (aq)

$\mathrm{Pb(NO_3)_2(aq)} + \mathrm{K_2SO_4}$ (aq) = PbSO₄(s) + 2KNO₃(aq)

3) Sodium carbonate (aq) + silver nitrate (aq) = silver carbonate (s) + sodium nitrate (aq)

$\mathrm{Na_2CO_3}$ (aq) + 2AgNO₃(aq) = 2Ag₂CO₃(s) + NaNO₃(aq)

4) Glucose (crist)+ oxygen(g) = carbon monoxide (g) + water (g)

$\mathrm{C_6H_{12}O_6}$ (crist)+ $\mathrm{O_2(g)} = \mathrm{CO_2(g)} + \mathrm{H_2O(g)}$

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