Question

hat mass of precipitate will form if 1.50l of concentrated pb(clo3)2 is mixed with 0.650 L of 0.130 M NaI

Answer 1

Answer on Question #48639, Chemistry, Other

**Task:**

What mass of precipitate will form if 1.50 l of concentrated $\mathrm{Pb(ClO_3)_2}$ is mixed with 0.650 L of 0.130 M NaI.

**Answer:**

$$\mathrm{Pb(ClO_3)_2} + 2\mathrm{NaI} = 2\mathrm{NaClO_3} + \mathrm{PbI_2} \downarrow$$ $$C_M = \frac{v}{V} \quad v = C_M V$$ $$v(\mathrm{Pb(ClO_3)_2}) = 0,13 \cdot 0,65 = 0,0845\ \mathrm{mol}$$ $$v(\mathrm{NaI}) = v(\mathrm{Pb(ClO_3)_2}) = 0,0845\ \mathrm{mol}$$ $$v = \frac{m}{M} \quad M(\mathrm{NaI}) = 150\ \mathrm{g/mol}$$ $$m(\mathrm{NaI}) = v(\mathrm{NaI}) \cdot M(\mathrm{NaI}) = 0,0845 \cdot 150 = 12,68\ \mathrm{g}$$

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