Question

What is the frequency of a radio wave with an energy of 4.536 × 10−24 J/photon?
Answer in units of Hz

Answer 1

Question #48502, Chemistry, Other

Question:

What is the frequency of a radio wave with an energy of $4.536 \times 10^{-24} \, \text{J/photon}$? Answer in units of Hz.

Answer:

The energy of the wave is related to its frequency with Plank's equation:

$$E = h v$$

Where $h$ is Plank's constant, $h = 6.626 \cdot 10^{-34} \, \text{J \cdot s}$.

According to this equation, frequency is the energy divided by Plank's constant:

$$v = \frac{E}{h} = \frac{4.536 \cdot 10^{-24} \, \text{J}}{6.626 \cdot 10^{-34} \, \text{J \cdot s}} = 6.887 \cdot 10^{9} \, \text{s}^{-1} = 6.887 \cdot 10^{9} \, \text{Hz}$$

So, $v = 6.887 \cdot 10^{9} \, \text{Hz}$.

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