Question

How many moles are in 484.25 g of ammonium phosphate [(NH3)3PO4]?
How many moles are in 75.46 g if Sulfuric Acid [H2SO4(aq)]?
How many moles are in 270.0 g of Dinitrogen pentoxide [N2O5]?
How many moles are in 546 g of tin IV fluoride [SnF4]

Answer 1

Answer on Question #48457, Chemistry, Other

Task:

How many moles are in 484.25 g of ammonium phosphate [(NH₃)₃PO₄]?

How many moles are in 75.46 g if Sulfuric Acid [H₂SO₄(aq)]?

How many moles are in 270.0 g of Dinitrogen pentoxide [N₂O₅]?

How many moles are in 546 g of tin IV fluoride [SnF₄]

Answer:

$$\nu = \frac {m}{M}$$ $$M \left(\left(N H _ {3}\right) _ {3} P O _ {4}\right) = 1 4 3 g / m o l$$ $$M \left(H _ {2} S O _ {4}\right) = 9 8 g / m o l$$ $$M \left(N _ {2} O _ {5}\right) = 1 0 8 g / m o l$$ $$M (S n F _ {4}) = 4 7 4. 8 g / m o l$$ $$\nu \left(\left(N H _ {3}\right) _ {3} P O _ {4}\right) = \frac {4 8 4 . 2 5}{1 4 3} = 3. 3 9 m o l$$ $$\nu \left(H _ {2} S O _ {4}\right) = \frac {7 5 . 4 6}{9 8} = 0, 7 7 m o l$$ $$\nu \left(N _ {2} O _ {5}\right) = \frac {2 7 0}{1 0 8} = 2, 5 m o l$$ $$\nu (S n F _ {4}) = \frac {5 4 6}{4 7 4 , 8} = 1, 1 5 m o l$$

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