Question

In the following reaction, how many grams of potassium phosphate, K3PO4, will be produced from 57.7 g of potassium hydroxide, KOH? 3KOH + H3PO4 ---> K3PO4 + 3H2O

Answer 1

Answer on Question#48409 – Chemistry – Other

In the following reaction, how many grams of potassium phosphate, K3PO4, will be produced from 57.7 g of potassium hydroxide, KOH? 3KOH + H3PO4 ---> K3PO4 + 3H2O

Solution:

3KOH + H3PO4 ---> K3PO4 + 3H2O

Mr(K3PO4)=3Ar(K)+Ar(P)+4Ar(O) (relative molecular masse g*mol⁻¹)

Mr(KOH)=Ar(K)+Ar(O)+Ar(H) (relative molecular masse g*mol⁻¹)

Mr(K3PO4)=212 g*mol⁻¹

Mr(KOH)=56 g*mol⁻¹

nA + xB = yC + zB

$$\frac{m(A)}{nM(A)} = \frac{m(C)}{yM(C)}$$

According to it:

$$\frac{m(KOH)}{3M(KOH)} = \frac{m(K3PO4)}{M(K3PO4)}$$

m(K3PO4)=72.8 g

Answer: 72.8 g

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