Question

Pd-100 has a half life of 3.6 days. If one had 6.02 x 10^23 atoms at the start, how many atoms would be present after 20.0 days?

Answer 1

Answer on Question #48318, Chemistry, Other

**Task:**

Pd-100 has a half life of 3.6 days. If one had $6.02 \times 10^{23}$ atoms at the start, how many atoms would be present after 20.0 days?

**Answer:**

$$\begin{array}{l} \text{ending amount} = \frac{\text{beginning amount}}{2^n} \\ n = \frac{\text{elapsed time}}{\text{half-life}} \\ n = \frac{20}{3.6} = 5.56 \\ \text{ending amount} = \frac{6.02 \cdot 10^{23}}{2^{5.56}} = 0.13 \cdot 10^{23} \\ \end{array}$$

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