Question #48291

A 12.0L sample of gas is compressed into a tank at 25°C and 4 atm. It is emptied into another storage tank at 3 atm. What do you expect the final temperature of the gas to be at its final volume?

Expert's answer

Answer on Question #48291, Chemistry, Other

**Task:**

A 12.0 L sample of gas is compressed into a tank at 25°C and 4 atm. It is emptied into another storage tank at 3 atm. What do you expect the final temperature of the gas to be at its final volume?

**Answer:**

The only components which will be unchangeable in this process are the amount of moles and volume of gas.


pV=vRTpV = vRTv=pVRT=4128,314(25+273)=0,02 molv = \frac{pV}{RT} = \frac{4 \cdot 12}{8,314 \cdot (25 + 273)} = 0,02 \text{ mol}T=p1VvR=3120,028,314=216,5 KT = \frac{p_1 V}{v R} = \frac{3 \cdot 12}{0,02 \cdot 8,314} = 216,5 \text{ K}t=216,5273=56,5Ct = 216,5 - 273 = -56,5^\circ \text{C}


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