Question

Calculate the heat of reaction using the average bond dissociation energies given in the introduction and your answer to Part B for the reaction
CH4 + 2O2 → CO2 + 2H2O

Answer 1

Question #48274, Chemistry, Other

Calculate the heat of reaction using the average bond dissociation energies given in the introduction and your answer to Part B for the reaction

$$\mathrm{CH_4} + 2\mathrm{O_2} \rightarrow \mathrm{CO_2} + 2\mathrm{H_2O}$$

Solvation

Energy of bonds:

- C—H 357.98 kJ/mol

- O₂ 494.04 kJ/mol

- H₂O 460.2 kJ/mol

- CO₂ 732 kJ/mol

$$Q = E_f - E_b$$

- Q is heat of reaction, kJ/mol;

- $E_f$ is energy of bonds are formed during reaction, kJ/mol;

- $E_b$ is energy of bonds are broken during reaction, kJ/mol.

$$Q = (4 \times 357.98 + 2 \times 494.04) - (2 \times 460.2 + 732) = 767.6\ \mathrm{kJ/mol}$$

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