Question

an alloyy of silver and copper weighs 28 ounces and 25 ounces in water, where copper losses 1/9 of its weighs and silver losses 1/10 of its weighs. how much of each metal is in the alloy?

Answer 1

Answer on Question #47954 - Chemistry - Other

Question

an alloy of silver and copper weighs 28 ounces and 25 ounces in water, where copper losses 1/9 of its weighs and silver losses 1/10 of its weighs. how much of each metal is in the alloy?

Answer:

Assume that $x$ is the mass of silver in the alloy and $y$ is the mass of copper in the alloy. Make system of equations and solve it:

$$\left\{ \begin{array}{c} x + y = 28 \\ \frac{1}{10}x + \frac{1}{9}y = 28 - 25 = 3 \end{array} \right.$$ $$\left\{ \begin{array}{c} x + y = 28 \\ \frac{1}{10}x + \frac{1}{9}y = 3 \end{array} \right.$$ $$\left\{ \begin{array}{c} x + y = 28 \\ 9x + 10y = 270 \end{array} \right.$$ $$\left\{ \begin{array}{l} x = 10 \\ y = 18 \end{array} \right.$$

So, the mass of silver in the alloy is 10 ounces and the mass of copper in the alloy is 18 ounces.

Answer: 10 ounces of silver and 18 ounces of copper are in the alloy.

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