Question

A pure gold ring contains 0.0116mmool(millimol) Au.
How many gold atoms does it contain?

Answer 1

Answer on Question #47940 – Chemistry – Other

Question:

A pure gold ring contains 0.0116mmol(millimol) Au.

How many gold atoms does it contain?.

Answer:

According to the definition of mole: 1 mole of substance consists of $6.022 \times 10^{23}$ elementary entities of that substance;

$$1 \text{ mole} = 6.022 \times 10^{23}$$

it means that in $0.0166 \times 10^{-3}$ moles of Au will be $\mathbf{x}$ elementary entities of that substance (atoms) of Au.

From this proportion $x = 0.0166 \times 10^{-3} \times 6.022 \times 10^{23} / 1 = 0.0999652 \times 10^{20} \approx 0.1 \times 10^{20}$ atoms of Au.

Answer: $0.1 \times 10^{20}$ atoms of Au

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