How many Liters of oxygen (O2) can be obtained from the decomposition of 100 grams of potassium chlorate (KClO3)? Assume zero degrees Celsius and 1 atmosphere pressure. The other product is potassium chloride.
m(KClO
3) = 100g
t = 0 ºC
P = 1 atmosphere
V(O
2) - ?
2KClO
3 ---> 2KCl + 3O
2
V(O2)=27,552L
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