Question #47824, Chemistry, Other
How many grams of sodium iodide, NaI, must be used to produce 15.3 g of iodine, I2
Answer:
n=m/MM(NaI)=150g/molM(I2)=254g/moln(I2)=2n(NaI)=m/M=15.3/254=0.06n(NaI)=2n(I2)=0.06∗2=0.12m(NaI)=0.12∗150=18g
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