Question #47824

How many grams of sodium iodide, NaI, must be used to produce 15.3 g of iodine, I2

Expert's answer

Question #47824, Chemistry, Other

How many grams of sodium iodide, NaI, must be used to produce 15.3 g of iodine, I2

Answer:

n=m/Mn = m / MM(NaI)=150g/molM (N a I) = 150 \mathrm{g/mol}M(I2)=254g/molM (I_2) = 254 \mathrm{g/mol}n(I2)=n(NaI)2=m/M=15.3/254=0.06n (I_2) = \frac{n (N a I)}{2} = m / M = 15.3 / 254 = 0.06n(NaI)=2n(I2)=0.062=0.12n (N a I) = 2 n (I_2) = 0.06 * 2 = 0.12m(NaI)=0.12150=18gm (N a I) = 0.12 * 150 = 18 \mathrm{g}


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