Question #47786

Number of moles present in 22 g of 2 CO gas

Expert's answer

Answer on Question #47786 - Chemistry – Other

Question

Number of moles present in 22 g of 2 CO gas

Answer:

Molar mass of CO gas equals:


M(CO)=M(C)+M(O)=12.011+15.999=28.01 g/molM(CO) = M(C) + M(O) = 12.011 + 15.999 = 28.01\ g/mol


Number of moles in 22 g of CO gas is:


n(CO)=m(CO)M(CO)=2228.01=0.785 moln(CO) = \frac{m(CO)}{M(CO)} = \frac{22}{28.01} = 0.785\ mol


Answer: 0.785 mol

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