Question

A nugget of gold with a mass of 521g is added to 50.0ml of water. the water level rises to a volume of 77.0mL. what is the denisty of the gold?

Answer 1

Question#47459 – Chemistry – Other

Question:

A nugget of gold with a mass of 521g is added to 50.0ml of water. The water level rises to a volume of 77.0mL. What is the density of the gold?

Answer:

The difference in volume is due to the volume of a gold nugget:

$$\Delta V = 77.0 \text{ml} - 50.0 \text{ml} = 27.0 \text{ml}$$

Density is defined as the mass of a body (in grams) per one cm³ (or ml) of its volume:

$$d = \frac{m}{V} = \frac{m_{Au}}{V_{Au}} = \frac{521 \text{g}}{27.0 \text{ml}} = 19.3 \text{g}/\text{ml} = 19.3 \text{g}/\text{cm}^3$$