Question

what is the normality of M/2 solution of H3PO4?

Answer 1

Question#47196 - Chemistry - Other

Question:

What is the normality of M/2 solution of $\mathsf{H}_3\mathsf{PO}_4$ ?

Answer:

The molarity is related to normality in the following way:

$C = f \times N$ , where $C$ is molarity, $N$ is normality and $f$ is an equivalence factor.

For $\mathsf{H}_3\mathsf{PO}_4$ the factor of equivalence is defined as

$f = \frac{1}{n}$ , where $n$ is for the number of protons $H^{+}$ resulted from the dissociation of $H_{3}PO_{4}$ .

$$\mathrm {H} _ {3} \mathrm {P O} _ {4} = 3 \mathrm {H} ^ {+} + \mathrm {P O} _ {4} ^ {3 -}$$

$n = 3$ , therefore:

$$f = \frac {1}{n} = \frac {1}{3};$$ $$N = \frac {C}{f} = \frac {0 . 5 M}{\frac {1}{3}} = 3 \times 0. 5 M = 1. 5 M$$