Question

A gem has a mass of 4.20g . When the gem is placed in a graduated cylinder containing 20.20mL of water, the water level rises to 21.80mL .
A graduated cylinder contains 155mL of water. A 17.0g piece of iron (density = 7.86g/cm3 ) and a 25.0g piece of lead are added. What is the new water level in the cylinder?

Answer 1

Question #46139, Chemistry, Other

The volume of displaced water is equal to volume of volume submerged body.

That's why: $V_{d.w.} = V_{iron} + V_{lead} = \frac{m_{iron}}{\rho_{iron}} + \frac{m_{lead}}{\rho_{lead}} = \frac{17g}{7.86g/cm^3} + \frac{25g}{11.31g/cm^3} = 4.37cm^3$

New water level in the cylinder is $(155+4.37)=159.37\ \mathrm{cm}^3$

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