Question #45399

10 gms of sodium cabonate is dissolved in 36 ml of water. Volume percentage of solution is ?

Expert's answer

Answer on Question #45399, Chemistry, Other

Task:

10 gms of sodium carbonate is dissolved in 36 ml of water. Volume percentage of solution is?

Answer:


w=m(Na2CO3)m(Na2CO3)+m(H2O)100%w = \frac {m \left(N a _ {2} C O _ {3}\right)}{m \left(N a _ {2} C O _ {3}\right) + m \left(H _ {2} O\right)} \cdot 100 \%M(H2O)=V(H2O)M \left(H _ {2} O\right) = V \left(H _ {2} O\right)w(Na2CO3)=1010+36100%=21%w \left(N a _ {2} C O _ {3}\right) = \frac {10}{10 + 36} \cdot 100 \% = 21 \%


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