Question

calculate the no. of atoms in 3.5 moles of cuso4

Answer 1

Answer on Question #44881 - Chemistry – Inorganic Chemistry

Question

calculate the no. of atoms in 3.5 moles of cuso4

Answer:

CuSO₄ is a salt. The elementary particle of this salt is molecule, so we can calculate the

number of molecules in 3.5 moles of CuSO₄.

Number of molecules in 3.5 moles of CuSO₄ equals:

$$= n(CuSO_4) \cdot A$$

n(CuSO₄) – number of moles of copper(II) sulfate, n(CuSO₄) = 3.5 mol.

$N_A$ – the Avogadro constant, $N_A = 6.022 \cdot 10^{23}$.

$$= 3.5 \cdot 6.022 \cdot 10^{23} = 2.108 \cdot 10^{24}$$

Each molecule of CuSO₄ has 6 atoms (1 atom of Cu plus 1 atom of S plus 4 atoms of O), so $2.108 \cdot 10^{24}$ molecules of CuSO₄ have $2.108 \cdot 10^{24} \cdot 6 = 1.265 \cdot 10^{25}$ atoms.

Answer: $1.265 \cdot 10^{25}$ atoms in 3.5 moles of CuSO₄.

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