Question

what is the ph value at 0.002m

Answer 1

Answer on Question #43726, Chemistry, Other

Question

what is the pH value at 0.002m

Solution

pH is defined as the decimal logarithm of the reciprocal of the hydrogen ion concentration in a solution:

$$\mathrm{pH} = -\lg[\mathrm{H}^{+}]$$

Thus, in 0.002 M solution of strong monobasic acid (complete dissociation, the concentration of hydrogen ions is equal to acid concentration):

$$\mathrm{pH} = -\lg[0.002] = 2.7$$

In 0.002 M solution of strong base (MOH, M = metal, the concentration of hydroxyl ions is equal to base concentration):

$$\mathrm{pH} = 14 - \mathrm{pOH} = 14 - (-\lg[0.002]) = 14 - 2.7 = 11.3$$

http://www.AssignmentExpert.com/