Question

there is a iodine oxide which has 254 grams Iodine & 80 grams oxygen so what's the formula of this molecular?

Answer 1

Answer on Question #43255 - Chemistry - Other

Question:

There is a iodine oxide which has 254 grams iodine & 80 grams oxygen so what's the formula of this molecular?

Solution:

1) Find amount of substance of iodine atoms in the iodine oxide:

$$n(\mathrm{I}) = \frac{m(\mathrm{I})}{M(\mathrm{I})} = \frac{254\ \mathrm{g}}{127\ \frac{\mathrm{g}}{\mathrm{mol}}} = 2\ \mathrm{mol}$$

2) Find amount of substance of Oxygen atoms in the iodine oxide:

$$n(\mathrm{O}) = \frac{m(\mathrm{O})}{M(\mathrm{O})} = \frac{80\ \mathrm{g}}{16\ \frac{\mathrm{g}}{\mathrm{mol}}} = 5\ \mathrm{mol}$$

3) As a result, the molar ratio of iodine and Oxygen in iodine oxide is 2 : 5 correspondingly, that means that there are 2 atoms of iodine and 5 atoms of Oxygen in 1 molecule of iodine oxide.

4) The molecular formula of iodine oxide is $\mathrm{I}_2\mathrm{O}_5$.

Answer: $\mathrm{I}_2\mathrm{O}_5$

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