Question

1.4g sample of KHP required 24.11cm3 of NaOH for its complete neutralization. Calculate the molarity of the NaOH used in titration?

Answer 1

Answer on Question #42974, Chemistry, Other

Question:

1.4 g sample of KHP required 24.11 cm $^3$ of NaOH for its complete neutralization. Calculate the molarity of the NaOH used in titration?

Solution:

1.4 g of KHP is equal to

$\mathrm{n(KHP)} = 1.4\mathrm{g} / 204.2\mathrm{g}^{*}\mathrm{mol}^{-1} = 6.86\mathrm{mmol}$

$\mathrm{n(KHP)} = \mathrm{n(NaOH)}$

$\mathrm{C(NaOH)} = 0.00686 \mathrm{~mol} / 0.02411 \mathrm{~L} = 0.284 \mathrm{~mol} / \mathrm{L}$

Answer: 0.284 mol/L

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