Question #42926

calculate the molarity for 32 grams of NaCl dissolved in 250 mL H20

Expert's answer

Answer on the question #42926, Chemistry, Other

Question:

calculate the molarity for 32 grams of NaCl dissolved in 250 mL H2O

Solution:

The molar concentration cic_{i} is defined as the amount of substance of the constituent nin_{i} divided by the volume of the mixture:


ci=niVc_{i} = \frac{n_{i}}{V}n(NaCl)=m(NaCl)M(NaCl)=3258,443=0.5475 moln(\mathrm{NaCl}) = \frac{m(\mathrm{NaCl})}{M(\mathrm{NaCl})} = \frac{32}{58,443} = 0.5475 \text{ mol}ci=0.54750.25=2.19 mol L1c_{i} = \frac{0.5475}{0.25} = 2.19 \text{ mol L}^{-1}


Answer: 2.19 mol L1^{-1}

http://www.AssignmentExpert.com/


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS