Question

When 45 g of an alloy, at 25 c, are dropped into 100.0 g of water, the alloy absorbs 228.5 cal of heat. If the final tempature of the alloy is 37 c, what is its specific heat?

Answer 1

Answer on Question #42911, Chemistry, Other

Question:

When 45 g of an alloy, at 25 c, are dropped into 100.0 g of water, the alloy absorbs 228.5 cal of heat. If the final tempature of the alloy is 37 c, what is its specific heat?

Solution:

The energy received by alloy can be calculated from the following equation:

$$Q = c \cdot m \cdot (T_f - T_i)$$ $$45 \cdot (T_f - T_i) \cdot c = 45 \cdot 12 \cdot c = 228.5,$$

where $T_f$ and $T_i$ are final and initial temperatures, $c$ – specific heat.

$$c = 228.5 / 45 / 12 = 0.42 \text{ cal/g}$$

Answer: 0.42 cal/g

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